Tuesday, April 21, 2009

UTS Surya Halim

Name : Surya Halim
Nim : 06507002

A company will decide to have an equipment which can saving an operation cost. Two optional are, each cost $1000 with usage time period of 5 years without unleft. A equipment will hope to saving $300 for annualy. B equipment will save $400 on the first year, decrease $50 every year. On interest of 7%, which equipment to be choose?
Answer :
Equipment A :
PW of cost = $1000
PW of benefit = $300 (P/A,7%,5) = 300(4.100) = $1230
B/C = 1230 / 1000 = 1.23

Equipment B :
PW of cost = $ 1000
PW of benefit = 400(P/A,7%,5) – 50 (P/G,7%,5) = 400(4.100) – 50(7.647) =$1258
B/C = 1258 / 1000 = 1.26

CHOOSE EQUIPMENT B



Machine X:
EUAB = $95
EUAC = 200(A/P,10%,6) – 50(A/F,10%,6) = 200(0.2296) – 50(0.1296) = $40

Machine Y:
EUAB = $120
EUAC = 700(A/P,10%,12) – 150(A/F,10%,12)
= 700(0.1468) – 150(0.0468) = $96

Machine Y – machine X:
ΔB / ΔC = (120 – 95) / (96 – 40) = 25/56 = 0.45 à Pilih machine X






CHOOSE EQUIPMENT A.

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