UTS Haris Abidin

Name : Haris Abidin
NIM : 06407055


A pump that is driven by a 20HP motor strength is needed to drain water from a tunnel. Number of pump hours operation for 1 year depending on uncertain. Pump unit that is required is estimated to haverain fall a period of 4 years. 2 alternatives considered:
Proposal A: propose to build a power line equipped with the electric motor 1 with a total cost of $ 14,000. Value remaining at the end of the year - 4 = $ 2000. Cost-per-hour flow of $ 8.4 operations; automaticmaintenance cost $ 1,200 per year. No tools required bantu equipment.
Proposal B: proposed to buy a gas motor for $ 5500. This motor does not have any residual value at the end of the year to-4. Costs for fuel and oil per hour = $ 4.2 operation. Maintenance cost of $ 1.5 per hour operation. And the wages paid when the motor runs $ 8 per hour.
Interest rate of 10%
Answer :
Solutions:
Proposal A:
TCA = total annual cost of the proposal ekivalen A
CRA = annual cost recovery ekivalen capital (capital recovery)
= (P - S) (A / P, 10%, 4) + S (0.10)
= ($ 14,000 - 2000) (0.3155) + 2000 (0.10)
= $ 3986
M = annual maintenance cost = $ 1200
C = cost per hour operating flow = $ 8.4
t = number of operating hours per year
TCA = CRA + M + C.t
= $ 3986 + 1200 + 8.4 t
= 5186 + 8.4 t

Proposal B:
TCB = total annual cost of the proposal ekivalen B
CRB fee = annual capital recovery ekivalen = (P - S) (A / P, 10%, 4) + S (0.10)
= ($ 5500) (0.3155)
= $ 1735.25
H = the cost of fuel, maintenance, wages per hour
= $ 4.2 + $ 1.5 + $ 8 = $ 13.7 per hour
t = number of operating hours per year
TCB = CRB + H.t
= $ 1735.25 + 13.7 t

TCA TCB =
5186 + 8.4 t = $ 1735.25 + 13.7 t
t = 651.08 hours ~ 651 hours
TCA = 5186 + 8.4 (651) = $ 10,654.4